要使得√3 sinα-cosα=(4m-6)/(4-m)有意义,求m的取值范围

问题描述:

要使得√3 sinα-cosα=(4m-6)/(4-m)有意义,求m的取值范围

1/2*sinα-根号3/2*cosα=2m-3/4-mcos60°*sinα-sin60°*cosα=2m-3/4-msin(α-60°)=2m-3/4-m所以2m-3/4-m∈【-1,1】2m-3/4-m≥-1,(2m-3+4-m)/(4-m)≥0,1≤m<42m-3/4-m≤1,(2m-3-4+m)/(4-m)≤0,m≤7/...