已知f(X)={cos丌x,x≤0,f(x-1)+1,X>0,则f(4/3)的值为

问题描述:

已知f(X)={cos丌x,x≤0,f(x-1)+1,X>0,则f(4/3)的值为

4/3>0
所以f(4/3)=f(4/3-1)+1
=f(1/3)+1
=[f(1/3-1)+1]+1
=f(-2/3)+2
=cos(-2π/3)+2
=-1/2+2
=3/2