设函数y=y(x)由方程xy+ln(x+e^2)+lny=0求y’(0) 答案是-(e^2+1/e)y^3-3y+2ax=0 确定y=(x),求y‘ y’‘
问题描述:
设函数y=y(x)由方程xy+ln(x+e^2)+lny=0求y’(0) 答案是-(e^2+1/e)
y^3-3y+2ax=0 确定y=(x),求y‘ y’‘
答
设函数y=y(x)由方程xy+ln(x+e^2)+lny=0求y’(0) 答案是-(e^2+1/e)
y^3-3y+2ax=0 确定y=(x),求y‘ y’‘