当-π/2≤x≤π/2时,函数fx=2sin（x+π/3）的最大值、最小值是多少
问题描述：
当-π/2≤x≤π/2时,函数fx=2sin（x+π/3）的最大值、最小值是多少
答
-π/2 ≤ x ≤ π/2
-π/2 + π/3 ≤ x + π/3 ≤ π/2 + π/3
-π/6 ≤ x + π/3 ≤ 5π/6
-1/2 ≤ sin(x + π/3) ≤ 1
-1 ≤ 2sin(x + π/3) ≤ 2
-1 ≤ f(x) ≤ 2
最大值是 2
最小值是 -1