求下列函数微分 y=[In(1-x)]^2
问题描述：
求下列函数微分 y=[In(1-x)]^2
答
dy/dx=y'=2[ln(1-x)]/(x-1)
∴dy=[2[ln(1-x)]/(x-1)]dx
答
y'=-2[In(1-x)]·[1/(1-x)]
=2In(1-x)/(x-1)