(4/9)^(-sinπ/6)-2lg(cos0)+(0.125)^(log2 (1/3))=

问题描述:

(4/9)^(-sinπ/6)-2lg(cos0)+(0.125)^(log2 (1/3))=

(4/9)^(-sinπ/6)-2lg(cos0)+(0.125)^(log2 (1/8))
=(4/9)^(-1/2)-2lg1+(1/8)^(-3)
=(2/3)^(-1/2×2)-0+8³
=3/2+512
=513.5