解方程: (1)(2x+1)2=3 (2)x2+2x-24=0 (3)2x2-4x+5=0 (4)4x2+4x+10=1-8x (5)9x2+6x+1=0 (6)x2-5x-14=0.
问题描述:
解方程:
(1)(2x+1)2=3
(2)x2+2x-24=0
(3)2x2-4x+5=0
(4)4x2+4x+10=1-8x
(5)9x2+6x+1=0
(6)x2-5x-14=0.
答
(1)(2x+1)2=3,2x+1=±3,解得:x1=−1+32,x2=−1−32;(2)x2+2x-24=0,(x+6)(x-4)=0,解得:x1=-6,x2=4;(3)2x2-4x+5=0∵b 2-4ac=16-4×2×5=-24<0,∴此方程没有实数根;(4)4x2+4x+10=1-8x,整理...