已知x2-5x-2004=0求﹛[﹙x-2﹚3-﹙x-1﹚2+1]/﹙x-2﹚﹜+1的值
问题描述:
已知x2-5x-2004=0求﹛[﹙x-2﹚3-﹙x-1﹚2+1]/﹙x-2﹚﹜+1的值
答
∵X^2-5X-2004=0∴[(X-2)³-(X-1)²+1]/(X-2)+1=[(X-2)³-(X-2+1)²+1]/(X-2)+1=[(X-2)³-(X-2)²-2(x-2)]/(X-2)+1=(x-2)²-(x-2)-2+1=x²-4x+4-x+2-2+1=x²-5x+4+1=x...