设函数f(x)=sin(2x+∮)(-兀
问题描述:
设函数f(x)=sin(2x+∮)(-兀
答
(1)2x+∮=π/2+kπ,将x=π/8带入,可以解得∮=-3π/4
(2)单调递增区间-π/2+2kπ