设函数f(x)=sin(2x+∮)(-兀

问题描述:

设函数f(x)=sin(2x+∮)(-兀

(1)2x+∮=π/2+kπ,将x=π/8带入,可以解得∮=-3π/4
(2)单调递增区间-π/2+2kπ