已知f(x)=ax5+bx3+cx-8,且f(d)=10,求f(-d)的值.
问题描述:
已知f(x)=ax5+bx3+cx-8,且f(d)=10,求f(-d)的值.
答
∵f(d)=ad5+bd3+cd-8=10
则ad5+bd3+cd=18
又a(-d)5+b(-d)3+c(-d)=-(a×d5+b×d3+c×d)=-18
所以a(-d)5+b(-d)3+c(-d)-8=-18-8=-26
所以f(-d)=-26.