y=sinxcosx+根号3cos^2 x,单调递增区间
问题描述：
y=sinxcosx+根号3cos^2 x,单调递增区间
答
sinxcosx=1/2sin2x,则y=sinxcosx+根号3cos^2 x
=1/2sin2x+根号3cos^2 x
=sin(2x+π/3)
2kπ-π/2