sin(Pai/12)-根号3*cos(Pai/12)等于多少,怎么算

问题描述:

sin(Pai/12)-根号3*cos(Pai/12)等于多少,怎么算

sin (π/12)-√3*cos(π/12) =2*[(1/2)*sin(π/12)-(√3/2)*cos(π/12)] =2*sin(π/12-π/3) =2sin(-π/4) =-2sin(π/4) =-2√2