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已知sin(540°+ɑ)=-1/3,求[sin(180°+ɑ)*cos(720°+α)*tan(540°+α)]/[cos(-α-180°)*tan(900°+α])

分类: 作业答案 • 2022-01-21 09:46:29
问题描述：

已知sin(540°+ɑ)=-1/3,求[sin(180°+ɑ)*cos(720°+α)*tan(540°+α)]/[cos(-α-180°)*tan(900°+α])

答

sin(540°+ɑ) = -sinα = -1/3
sinα = 1/3
[sin(180°+ɑ)cos(720°+α)tan(540°+α)]/[cos(-α-180°)tan(900°+α)]
= (-sinɑcosαtanα)/(-cosαtanα)
= sinɑ
= 1/3

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