已知x2-y2=12,x-y=2,则x+y= _ .

问题描述:

已知x2-y2=12,x-y=2,则x+y= ___ .

∵x2-y2=12,x-y=2,
∴x2-y2=(x+y)(x-y)=2(x+y)=12,
∴x+y=6.
故答案为:6.