x(16x-5)-(4x+1)(4x-1)=11 3x(x+2)+2(x+1)(x-1)=5(x^2+8)解方程
问题描述:
x(16x-5)-(4x+1)(4x-1)=11 3x(x+2)+2(x+1)(x-1)=5(x^2+8)解方程
答
(1)
x(16x-5)-(4x+1)(4x-1)=11
16x²-5x-(16x²-1)=11
16x²-5x-16x²+1=11
-5x=10
x=-2
(2)
3x(x+2)+2(x+1)(x-1)=5(x^2+8)
3x²+6x+2x²-2=5x²+40
6x=42
x=7
答
x(16x-5)-(4x+1)(4x-1)=11
16x²-5x-16x²+1=11
-5x=10
x=-2
3x(x+2)+2(x+1)(x-1)=5(x^2+8)
3x²+6x+2x²-2=5x²+40
6x=42
x=7
答
x(16x-5)-(4x+1)(4x-1)=11 16x² -5x-(16x² -1)=11-5x+1=11-5x=10x=-23x(x+2)+2(x+1)(x-1)=5(x^2+8)3x² +6x+2(x² -1)=5x^2+405x² +6x-2=5x^2+406x=42x=7如果本题有什么不...