计算[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]÷[4(x-2)]=_.
问题描述:
计算[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]÷[4(x-2)]=______.
答
原式=[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]×
1 4(x−2)
=(x-2)+3(x+2)-2(x+1)2=x-2+3x+6-2x2-4x-2
=-2x2+2.
故答案为-2x2+2.