y=sinxcosx+根号3cos^2x的最小正周期是
问题描述：
y=sinxcosx+根号3cos^2x的最小正周期是
答
y=1/2*sin2x+√3(1+cos2x)/2
=sin2x*1/2+cos2x*√3/2+√3/2
=sin2xcosπ/3+cos2xsinπ/3+√3/2
=sin(2x+π/3)+√3/2
T=2π/2=π