求证:(根号3)*sinα+cosα=2sin(α+π/6)

问题描述:

求证:(根号3)*sinα+cosα=2sin(α+π/6)

左边=2(sinα*√3/2+cosα*1/2)
=2(sinαcosπ/6+cosαsinπ/6)
=2sin(α+π/6)=右边
命题得证