3.△ABC中,角A,B,C所对的边分别为a,b,c,B=π/3,cosA=4/5,b=√3 (1)sinC值 (2)△面积
问题描述:
3.△ABC中,角A,B,C所对的边分别为a,b,c,B=π/3,cosA=4/5,b=√3 (1)sinC值 (2)△面积
答
sinC=sin(120-A)=sin120cosA-cos120sinA=(根下3)/2*(4/5)+(1/2)*(3/5)=(4倍根下3 +3)/10
a=b/sinB*sinA=2*3/5=6/5
S=0.5absinC=0.5*6/5*(根下3)*(4倍根下3 +3)