cos(π-2a)/sin(a-π/4)=-√2/3 求cosa+sina=_ 求推导
问题描述:
cos(π-2a)/sin(a-π/4)=-√2/3 求cosa+sina=_ 求推导
答
cos(π-2a)/sin(a-π/4)=-√2/3-con2a/√2(sina-cona)=-√2/3con2a/(sina-cona)=1/3[(cona)^2-(sina)^2]/(sina-cona)=1/3(cona+sina)(cona-sina)/(cona-sina)=1/3cona+sina=1/3