因式分解:(a^2-3a)^2+4a^2-12a+4=___________ n(n+1)(n+2)(n+3)+1=——————

问题描述:

因式分解:(a^2-3a)^2+4a^2-12a+4=___________ n(n+1)(n+2)(n+3)+1=——————
(x^2-x)^2-8x^2+8x+12=_____________

1 (a^2-3a)^2+4a^2-12a+4=(a²-3a)²+4(a²-3a)+4=(a²-3a+2)²=[(a-1)(a-2)]²=(a-1)²(a-2)²2.n(n+1)(n+2)(n+3)+1=[n(n+3)][(n+1)(n+2)]+1=(n²+3n)[(n²...