cos(-17/6π)+tan(-17/6π)
问题描述:
cos(-17/6π)+tan(-17/6π)
答
cos(-17/6π)+tan(-17/6π)
=cos(7/6π-4π)+tan(1/6π-3π)
=cos(7/6π)+tan(1/6π)
=-√3/2+√3/3
=-√3/6
答
cos(-17/6π)+tan(-17/6π)
=-cos(π/6)+tan(π/6)
=-√3/2+√3/3
=-√3/6