y=In √[(2x-1)/(x+1)],求导?
问题描述:
y=In √[(2x-1)/(x+1)],求导?
答
y=ln √[(2x-1)/(x+1)]
=(1/2)(ln(2x-1)-ln(x+1))
y'=(1/2)((2/(2x-1))-(1/(x+1))
=3/(2(2x-1)(x+1))