当z=1-i/√2时,z∧100+z∧50+1的值等于多少
问题描述:
当z=1-i/√2时,z∧100+z∧50+1的值等于多少
答
z=(1-i)/√2=e^(-iπ/4)
z∧100+z∧50+1=e^(-100iπ/4)+e^(-50iπ/4)+1
=-1-i+1
=-i