(x+2/x+1)-(x+4/x+3)=(x+6/x+5)-(x+8/x+7)求过程
问题描述:
(x+2/x+1)-(x+4/x+3)=(x+6/x+5)-(x+8/x+7)求过程
答
1+1/x+1-1-1/x-3=1+1/x+5-1- 1/x+71/x+1-1/x+3-1/x+5+1/x+7=0( x+3-x-1)/(x+1)(x+3)=(x+7-x-5)/(x+5)(x+7)( x+1)(x+3)=(x+5)(x+7) x^2+4x+3=x^2+12x+35 8x=-32 x=-4