f(x+1)=x平方减3x加2,求f(庚号2)的值.
问题描述:
f(x+1)=x平方减3x加2,求f(庚号2)的值.
答
令x+1=√2
则x=√2-1
所以f(√2)=(√2-1)²-3(√2-1)+2
=(3-2√2)-(3√2-3)+2
=8-5√2