等比数列{an}中,an>0,a3a4=4,则log2a1+log2a2+…+log2a6值为( ) A.5 B.6 C.7 D.8
问题描述:
等比数列{an}中,an>0,a3a4=4,则log2a1+log2a2+…+log2a6值为( )
A. 5
B. 6
C. 7
D. 8
答
在等比数列中,a3a4=a1a6=a2a5=4,
log2a1+log2a2+…+log2a6=log2(a1a2…a6)=log226=6.
故选:C.