2x3/1+3x4/1+4x5/1.41x42/1的和

问题描述:

2x3/1+3x4/1+4x5/1.41x42/1的和

an=(n+1)(n+2)=(n+1)^2+(n+1)
原式=Sn=2^2+3^2+……+41^2+2+3+……+41
=41*42(82+1)/6 -1+40(2+41)/2
=23821-1+860=24680