分解因式:(x²+x-4)(x²+x+3)+10=
问题描述:
分解因式:(x²+x-4)(x²+x+3)+10=
答
(x²+x-4)(x²+x+3)+10
=(x²+x)²-(x²+x)-12+10
=(x²+x)²-(x²+x)-2
=(x²+x-2)(x²+x+1)
=(x+2)(x-1)(x²+x+1)