a=2-√2,b=2+√2求(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²

问题描述:

a=2-√2,b=2+√2求(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²

(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²)=【a²b(a+b)分之(a+b)²】/【a(a-b)分之((a+b)(a-b))】=a²b分之(a+b)*(a+b)分之a=1/(ab)=1/【(2-√2)*(2+√2)...