a=2-√2,b=2+√2,求(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
问题描述:
a=2-√2,b=2+√2,求(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
答
(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)=【a²b(a+b)/(a+b)²】/【a(a-b)/((a+b)(a-b))】=a²b/(a+b)*(a+b)/a=ab=(2-√2)*(2+√2)=2²-2=2【欢迎追问,】...