(1+1/3+1/5+1/7)×(1/3+1/5+1/7+1/9)−(1+1/3+1/5+1/7+1/9)×(1/3+1/5+1/7).

问题描述:

(1+

1
3
+
1
5
+
1
7
)×(
1
3
+
1
5
+
1
7
+
1
9
)−(1+
1
3
+
1
5
+
1
7
+
1
9
)×(
1
3
+
1
5
+
1
7
).

1
3
+
1
5
+
1
7
=a,
(1+
1
3
+
1
5
+
1
7
)×(
1
3
+
1
5
+
1
7
+
1
9
)−(1+
1
3
+
1
5
+
1
7
+
1
9
)×(
1
3
+
1
5
+
1
7
)

=(1+a)×(a+
1
9
)-(1+a+
1
9
)×a
=a+
1
9
+a2+
1
9
a-a-a2-
1
9
a
=
1
9