(x的平方-y的平方)分之2xy+(x+y)分之x

问题描述:

(x的平方-y的平方)分之2xy+(x+y)分之x

原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)
=(2xy+x²-xy)/(x+y)(x-y)
=(x²+xy)/(x+y)(x-y)
=x(x+y)/(x+y)(x-y)
=x/(x-y)3-x/x-2/{x+2-(x-2分之5)}其中x=2根号2采纳我,重新问