设y+xe的y次方=1,求dx分之dy
问题描述:
设y+xe的y次方=1,求dx分之dy
答
dy+d(x*e^y)=d(1)
dy+xd(e^y)+e^ydx=0
dy+xe^ydy+e^ydx=0
(xe^y+1)dy=-e^ydx
dy/dx=-e^y/(xe^y+1)