当x趋于0时,ln(1-x^2)/(x(1-2x))的极限是0,0.5 ,还是无穷大
问题描述:
当x趋于0时,ln(1-x^2)/(x(1-2x))的极限是0,0.5 ,还是无穷大
答
lim(x-->0)ln(1-x^2)/(x(1-2x)) (0/0型)
=lim(x-->0)[-2x/(1-x²)]/(1-4x) (罗比达法则)
=0