1/6a^4b^8-[(-ab)^-3*(a^2b^4)^2]/[(-1/2ab)^-3]
问题描述:
1/6a^4b^8-[(-ab)^-3*(a^2b^4)^2]/[(-1/2ab)^-3]
答
1/6a^4b^8-[(-ab)^-3*(a^2b^4)^2]/[(-1/2ab)^-3]
=1/6a^4b^8-[-a^(-3)b^(-3)*(a^4b^8]/[(-8a^(-3)b^(-3)]
=1/6a^4b^8-[-ab^5]/[(-8a^(-3)b^(-3)]
=1/6a^4b^8+1/8a^4b^8
=7/24a^4b^8