已知x+y=-5,xy=6,则x3y-xy3=_.
问题描述:
已知x+y=-5,xy=6,则x3y-xy3=______.
答
∵x+y=-5,xy=6,
∴(x-y)2=(x+y)2-4xy=1,
∴x-y=±1,
∴x3y-xy3=xy(x+y)(x-y)=-30(x-y),
当x-y=1时,原式=6×(-5)×1=-30;
当x-y=-1时,原式=6×(-5)×(-1)=30.