如图,在正方形ABCD中,点 E 、F是对角线BD上,且BE=EF＝FD,联结AECE\CF
问题描述：
如图,在正方形ABCD中,点 E 、F是对角线BD上,且BE=EF＝FD,联结AECE\CF
答
证明：（1）∵四边形ABCD是正方形,∴AD = CD,∠ADF =∠CDF．在△ADF和△CDF中,∵AD = CD,∠ADF =∠CDF,DF = DF,∴△ADF≌△CDF∴AF = CF（2）联结AC,AC与BD相较于点O．∵四边形ABCD是正方形,∴AC⊥BD,OA = OC,OB = O...