化简求值:a与b互为相反数,x与y互为倒数,若m=-(-1/3),求(xy/3m)+(a+b/2012)的值
问题描述:
化简求值:a与b互为相反数,x与y互为倒数,若m=-(-1/3),求(xy/3m)+(a+b/2012)的值
答
答案=1请问可以写过程吗?a与b互为相反数,则a+b=0,,x与y互为倒数,则xy=1,m=-(-1/3),则m=1/3,则(xy/3m)+(a+b/2012)=3x1/3分之1+0/2012=1+0=1