因式分解:(x²+1)²-x²+x(x-2)(x²+x+1)

问题描述:

因式分解:(x²+1)²-x²+x(x-2)(x²+x+1)

原式=x^4+x²+1+x(x-1)(x²+x+1)-x(x²+x+1)=x(x-1)(x²+x+1)+x^4-x³-x+1=x(x-1)(x²+x+1)+x³(x-1)-(x-1)=(x-1)[x(x²+x+1)+(x-1)(x²+x+1)]=(x-1)(x²+x+1)(2x-1)解法2...