已知log(2)3=a,log(3)7=b试用a,b表示log(2)14

问题描述:

已知log(2)3=a,log(3)7=b试用a,b表示log(2)14

log(2)3=a,log(3)7=b
所以,log(2)7=ab
1+log(2)7=ab+1
log(2)2+log(2)7=ab+1
log(2)(2×7)=ab+1
log(2)14=ab+1