y=-1/2cot(π/3-2x)的周期为?单调区间为?
问题描述:
y=-1/2cot(π/3-2x)的周期为?单调区间为?
答
y=-1/2cot(π/3-2x)=1/2cot(2x-π/3)
周期T=π/2
单调区间
kπ=即kπ/2+π/6单调区间(kπ/2+π/6,(k+1)π/2+π/6) k=1,2,3,.
单调递减