分式乘除法：已知x-3y=0,求2x+y/x²-2xy+y²×(x-y)的值

分类: 作业答案 • 2022-01-09 18:04:15

问题描述：

答

x-3y=0
x=3y
2x+y/x^2-2xy+y^2×(x-y)
=(2x+y)/(x-y)^2*(x-y)
=(2x+y)/(x-y)
=(6y+y)/(3y-y)
=7y/2y
=7/2