L是圆周x^2+y^2=2,求对弧长的曲线积分∮L(x^2+y^2)ds?
问题描述:
L是圆周x^2+y^2=2,求对弧长的曲线积分∮L(x^2+y^2)ds?
答
令,x=√2cost,
y=√2cost
则,ds=√2dt
则,
∮L(x^2+y^2)ds=∫2√2dt=4√2π