(2a根号3ab²)-(b/6根号27a³)-(6ab根号a/3)(b≥0)

问题描述:

(2a根号3ab²)-(b/6根号27a³)-(6ab根号a/3)(b≥0)

2a根号(3ab²)-(b/6)根号(27a³)- 6ab根号(a/3)
=2根号3*ab根号a - (1/2)*ab根号a - 2根号3*ab根号a
=- (1/2)*ab根号a