若方程X/X-1=m+2m/1-X有增根

问题描述:

若方程X/X-1=m+2m/1-X有增根
增根是多少?此时M等于多少

答:
方程x/(x-1)=m+2m/(1-x)有增根
x/(x-1)=m*[(x-1-2)/(x-1)]
x/(x-1)=m*(x-3)/(x-1)
x=mx-3m
(m-1)x=3m
增跟x=1,代入得:
m-1=3m
2m=-1
m=-1/2