若函数在y=2xˆ2+4x处的导数是8,求x○的值.,
问题描述:
若函数在y=2xˆ2+4x处的导数是8,求x○的值.,
答
x₀ = 1
y = 2x² + 4x
y' = 4x + 4
y'|(x₀) = 8 => 4x₀ + 4 = 8 => x₀ = 1