(1) x^2 + xy - 6y^2 - x + 7y - 2
问题描述:
(1) x^2 + xy - 6y^2 - x + 7y - 2
(2) 6x^2 + xy - 2y^2 + 2x - 8y - 8
答
(1) x^2 + xy - 6y^2 - x + 7y - 2 =(x+3y)(x-2y)+[(x+3y)*(+1)+(x-2y)*(-2)]-2=(x+3y-2)(x-2y+1)(2) 6x^2 + xy - 2y^2 + 2x - 8y - 8=(2x-y)(3x+2y)+[(2x-y)*4+(3x+2y)(-2)]-8=(2x-y-2)(3x+2y+4)