已知sin（a+b）=1 则tan（2a+b）+tanb
问题描述：
已知sin（a+b）=1 则tan（2a+b）+tanb
答
4tan(a/2)=1-tan(a/2)得 2tan(a/2)/(1-tan(a/2))=1/2
tan(a)=1/2
4sinb=sin(2a+b)+sinb=2sin(a+b)cos(a)
2sinb=sin(2a+b)-sinb=2cos(a+b)sin(a)
相除得2tan(a)=tan(a+b)=1a+b=π/4