x2+y2=3,xy=1,求x-y..
问题描述:
x2+y2=3,xy=1,求x-y..
答
xy=1,2xy=2(x-y)^2=x^2-2xy+y^2=x^2+y^2-2xy=3-2=1所以x-y=1
x2+y2=3,xy=1,求x-y..
xy=1,2xy=2(x-y)^2=x^2-2xy+y^2=x^2+y^2-2xy=3-2=1所以x-y=1